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PEMDAS Quiz!

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Author: mia555

Group: Default

Filesize: 66.23 kB

Date added: 2015-09-04

Rating: 5

Downloads: 241

Views: 194

Comments: 17

Ratings: 1

Times favored: 0

Made with: Algodoo v2.1.0

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plz do it
5 mins
3 questions
really hard
good at maths good at this
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1. 160
2. 9
3. 9
/
V
/
V
/
and V
The second equation is not written correctly because it is missing a multiplication operator. 6÷2(2+1) should be written: 6÷2*(2+1)

Also, your answer is wrong because according to PEMDAS, you should do the multiplication "2*(2+1) = 6" before you do the division. Then when you do the division: "6÷6" the answer is ONE (not 9)!
Last edited at 2015/09/04 07:38:04 by Xray
The first one is bigg maybe 910? Because i know that first goes * then / then + and- but what about this ''^'' times thing. I don't remember is it goes first or second after * .
The second must be 9
The last one must be 65
@ Xray, you're wrong :o

The parantheses are telling us to multiply, so no multiplication operator is needed.

also the answer was wright

6÷2(2+1) - first parantheses
= 6÷2*3 - now multiplication and division starting from the left
= 3*3
= 9

:)
Last edited at 2015/09/04 21:34:47 by T'wind
Well, it's been a very long time since I was in school! :lol:

My logic (right or wrong) is that, according to the order of operations, you are supposed to do the multiplication BEFORE you do the division: MDAS. So, for 6÷2*3, my assumption is you would first calculate the multiplication (2*3) which is 6, and then you would do the division, which would be 6÷6. What is wrong with that logic?
order of operations

1. parantheses
2. exponents and roots
3. multiplication and division from left to right
4. addition and subtraction from left to right

your logic was used until the end of the nineties
Last edited at 2015/09/04 23:57:14 by T'wind
Xray MD and AS are supposed to be from left to right
so if it was 10/2*3 you do 10/2=5 and then multiplication: 5*3=15
same for AS 56-8+2=56-8=48+2=50:) hope this is better understanding
vaidas exponents (E) is the ^ so 2^2=2*2=4
4^7=4*4*4*4*4*4*4=16384
Okay, I guess it was the "from left to right" rule that I failed at. Thanks for explaining guys! :tup:
mia555 i do know what they are and how they are countable.
I just cant count it correctly if i have no clue if the ''^'' is higher by the order of moves.
If ''^'' is higher then:
(4-2)^2*8/4+1 goes like this
4-2 = 2
2^2*8/4+1 now in the priority order can be and''^'' and *. But lets say its ^
2^2 = 2*2*2 = 4*2 = 8
8*8 = 64
64/4 = 16
16 + 1 = 17
Oh yeah i like the hidden box:)
its X^2 = X*X X^5= X*X*X*X*X
X^2= 2 X's multiplied
X^5= 5 X's multiplied
so its:
(4-2)^2*8/4+1
=(2)^2*8/4+1
=4*8/4+1 Mult Div left to right
=8+1
=9
there is a lot of maths here
Xray, in pemdas, If there is multiplication and division, you move left to right!
Alasmyfoe, Yes, I know that. Read my previous comment!
and all the other ones xD